June 26
Calendula Officinalis
can you explain to me what does it mean?’50% ethanol(1:9,w/w)’?
I found a documentation about:’preparation of calendula extract’, i did not understand The used quantity for ethanol and flowers
The Calendula officinalis L. dried flowers were ground in a knife mill into fine particles (0.3 mm – mean diameter). The powdered drug was macerated with 50% ethanol (1:9, w/w) at 25 °C for 5 days. This mixture was subjected to mechanical agitation at 870 rpm (Fisatom, model 713 D) for 1 h at the beginning and end of the maceration period. Afterwards, the extract was filtered and dried at 40 °C in a stove with air circulation. Finally, the residue was resuspended into 50% hydroalcoholic solution (200 mL) and stored at −20 °C. The obtained concentrated extract contained 15.7% dry weight.
thank you!
“The powdered drug was macerated with 50% ethanol (1:9, w/w)”
means…
a) 1 gram of the drug + 9 grams of the ethanol solution mixed together
b) the ethanol solution was a 50% solution…probably 50:50 v/v in water.. ie.. 1 L ETOH + 1 L H2O —> 50% v/v ETOH
c) w/w means weight per weight. v/v means volume per volume
btw…macerated is like marinated. stewed in juices.
Growing calendula: Calendula Officinalis
